I suggest you ...

Standard normal distribution table, Theta(z)=1/sqrt(2*pi) INTe^-t²/2dt (over -inifity to z) = P(Z<=z), Z~N(0,1);

Usage: Just type in a value for z (negative or positive) and press the Standard normal distribution table button.

Should also work backwards (then you put in the probability (0<p<1) and get the z instead) using Shift-Button or corresponding.

z values are between ~-3.2 (p=0 for z<-3.2) and 0,000 (p=0.5) and ~3.2 (p=1 for z>3.2)

1 vote
Vote
Sign in
(thinking…)
Password icon
Signed in as (Sign out)
You have left! (?) (thinking…)
Gunnar shared this idea  ·   ·  Flag idea as inappropriate…  ·  Admin →

0 comments

Sign in
(thinking…)
Password icon
Signed in as (Sign out)
Submitting...

Feedback and Knowledge Base